TRINITY MATH TRIATHLON

Solutions:  January 2002 Team Competition

1.  Solutions:
a.  37/2
b.  12
c.  x = 6
d.  True
e.  True
2. 

3.  Solutions

a.  4 (boxes)
b.  144 (units2)
4.  Solution
A = 5
B = 13
C = 21
D = 25
E = 31
F = 33
G = 36
H = 39
I = 47
J = 50
5.  Three solutions are possible:
Solution #1: E = 9, I = 7, R = 4, W = 3, Z = 1, V = 2.  1397 + 1397 = 2794
Solution #2: E = 9, I = 7, R = 4, W = 8, Z = 1, V = 3.  1897 + 1897 = 3794
Solution #3: E = 9, I = 7, R = 4, W = 8, Z = 2, V = 5.  2897 + 2897 = 5794

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